A cylindrical conductor of length 'l' and uniform area of cross section 'A' has resistance 'R' another conductor of length 2.5 l and resistance 0.5R of the same material has area of cross section...
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Answer:
Explanation: 5A
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Given :
- For first conductor:
- Length ( L₁) = l
- Area of cross section (A₁) = A
- Resistance (R₁) = R
- For second conductor:
- Length ( L₂) = 2.5 l
- Resistance (R₂) = 0.5 R
To find :
- Area of cross section of second conductor (A₂)
Solution :
- We know that, resistance of a conductor is given by,
R = (ρL)/(A) where ρ is the resistivity of the conductor.
- ∴ ρ = (RA)/(L)
- The resisitivity of a given conductor depends only on the material of the conductor. We are given that both conductors have the same material. Hence , resistivity of both materials will be the same.
- ∴ ρ₁ = ρ₂
∴ (R₁.A₁)/L₁ = (R₂.A₂)/L₂
∴ (R.A)/l = (0.5R × A₂)/2.5l
- ∴ A₂ = 5A
Answer : The area of cross section of the second conductor will be 5A.
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