Question

if z=-2/1+root3i , arg(z) is_____

Answer 1

Answer:

After you get to the point where you write z=−12−i2, you can rewrite this as z=(122–√)(−2–√2−i2–√2). You can then use the formula z=reiθ, where r=|z|, and eiθ=cosθ+isinθ, where θ=arg(z). Here θ=5π4+2kπ,k∈Z. If Arg(z)∈[0,2π), Arg(z)=5π4. If Arg(z)∈(−π,π], Arg(z)=−3π4.

Step-by-step explanation: