Question

a cylindrical roller 2.5 m in length and 1.75 metre in radius when rolled on a row was found in to corner the area of 5500 and how many revolution did it make

Answer 1

no:of revolutions=area covered/curved surface area of cylinder
                            =5500/2*22/7*1.75*2.5        (since C.S.A of cylinder=2*pi*r*h)
                           =5500/44*0.25*2.5
                           =5500/44*0.625
                           =5500/27.5
                           =200 revolutions
therefore the answer is 200 revolutions
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