Question

A dealer sold a camera for Rs.1080 gaining 1/8 of its cost price.Find:
(¡)the cost price of the camera.
(¡¡)The gain per cent earned by the dealer.

Answer 1

Hii..
Here is your answer..

Solution:-
Let the CP be x
Gain =1/8 of Cp
$= > \frac{1}{8} of \: x \\ = > \frac{x}{8}$
Selling Price=1080
SP=Cost Price+Gain
$= > 1080 = x + \frac{x}{8} \\ = > 1080 = \frac{8x + x}{8} \\ = > 1080 = \frac{9x}{8}$
$= > x = \frac{1080 \times 8}{9} \\ = > x = 960$
Therefore,
Cost Price =₹960

Now,
Gain =x/8
$= > \frac{x}{8} \\ = > \frac{960}{8} \\ = > 120$
We know that,
$gain\% = \frac{gain}{cp} \times 100 \\ = > \frac{120}{960} \times 100 \\ = > 12.5$
Hence,
Gain is 12.5℅

Hope it helps uh...✌️✌️✌️