Question

Root 2 x square - 3 x - 2 root 2 = 0 , find the solution

Answer 1

Answer:

hope you UNDERSTOOD this answer

Answer 2

Concept Introduction:-

It could take the shape of a word or a number representation of the quantity's arithmetic value.

Given Information:-

We have been given that $Root 2 x square - 3 x - 2 root 2 = 0$

To Find:-

We have to find that the value of $Root 2 x square - 3 x - 2 root 2 = 0$

Solution:-

According to the problem

$\sqrt{2}x^2-3x-2\sqrt{2}=0 \\\Rightarrow x^{2} -\frac{3x}{\sqrt{2}}-2=0$

Here, $a=1,b=-\frac{3}{\sqrt2},c=-2$

$x^{2}-\frac{3x}{\sqrt2}=2\\\left(\frac{-\mathrm{b}}{2 \mathrm{a}}\right)^{2}=\left(\frac{-\left(\frac{-3}{\sqrt{2}}\right)}{2(1)}\right)^{2}=\frac{9}{8}$

Adding $\frac{9}{8}$ on both sides,

$\Rightarrow x^{2}-\frac{3}{\sqrt{2}} x+\frac{9}{8}=2+\frac{9}{8}$

$\Rightarrow\left(x-\frac{3}{2 \sqrt{2}}\right)^{2}=\frac{25}{8}$

$\Rightarrow x-\frac{3}{2 \sqrt{2}}=\pm \frac{5}{2 \sqrt{2}}$

$\Rightarrow x-\frac{3}{2 \sqrt{2}}=\frac{5}{2 \sqrt{2}} \text { and } x-\frac{3}{2 \sqrt{2}}=-\frac{5}{2 \sqrt{2}}$

$\Rightarrow \mathrm{x}=2 \sqrt{2} \text { and } \mathrm{x}=-\frac{1}{\sqrt{2}}$

Final Answer:-

The correct answer is $-\frac{1}{\sqrt2}$.

#SPJ2