Question

A deep rectangular pond of surface area A.
containing water (density = p), specific heat
capacity = s), is located in a region where the
outside air temperature is at a steady value of
26°C. The thickness of the frozen ice layer in this
pond, at a certain instant is x.
Taking the thermal conductivity of ice as K, and its
specific latent heat of fusion as L, the rate of
increase of the thickness of ice layer, at this
instant, would be given by [NEET-2019 (Odisha)]
(1) 26K1px(L + 4s) (2) 26K/px(L - 4s)
(3) 26K/(px*2L) (4) 26K/(pxL)​

Answer 1

Answer:

Explanation:

Given A deep rectangular pond of surface area A.  containing water (density = p), specific heat  capacity = s), is located in a region where the  outside air temperature is at a steady value of  26°C. The thickness of the frozen ice layer in this  pond, at a certain instant is x.

Given thickness of ice at a certain instant is x, assuming that at any instant thickness of ice is x, time taken to form more thickness that is dx is dt

So mL = KA l 26 – 0 l dt / x

   So A dx ρ L = KA 26 dt / x

  So dx / dt = 26 K / ρ L x

Answer 2

Answer:

26 K/pxL

Explanation:

Explaination can be reffered by another answer given above

These r just steps ...

Thank you