Question

A dice is thrown 100 times and the outcome are noted as given below : outcome : 1,2,3,4,5,6, frequency : 21,14,18,15,23,9, when a dice is thrown at random what is the probability of getting a 3 b.6 c.4 d. 1?​

Answer 1

Step-by-step explanation:

a) 18/100 => 9/50

b) 9/100

c) 15/100 => 3/20

d) 21/100

Answer 2

i) P(Getting a number 3) = 7/50

ii) P(Getting a number 5) = 9/50

iii) P(Getting a number 4) =23/100

iv) P(Getting an even number) =47/100

v) P(Getting an odd number) =53/100

Step-by-step explanation:

The given table:

Outcomes: 1 2 3 4 5 6

Frequency: 21 9 14 23 18 15

Total number of possible outcomes = 100

i) 3

Number of favourable outcomes = 14

∴ P(Getting a number 3) =14/100=7/50

ii) 5

Number of favourable outcomes = 18

∴ P(Getting a number 5) = 18/10=9/50

iii)4

Number of favourable outcomes = 23

∴ P(Getting a number 4) =23/100

iv) Even number

Number of favourable outcomes(2, 4, 6) = 9 + 23 + 15 = 47

∴ P(Getting an even number) =47/100

v) Odd number

Number of favourable outcomes(1, 3, 5) = 21 + 14 + 18 = 53

∴ P(Getting an odd number) = 53/100

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