Question

A dice is thrown twice and sum of numbers appearing is observed to be 7

Answer 1

1. Answer:  Step-by-step explanation: Possible outcomes= (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1),                (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)  Favorable outcomes= (1,6), (2,5), (3,4), (4,3), (5,2), (6,1)