Question

A die is thrown again and again until 306 is a octane find the probability of obtaining the 3rd 6 in 6th throw

Answer 1

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We need to find the P (obtaining the third six in 6th throw of the die) = P (2 sixes in first 5 throws) + P (1 six in sixth throw)

Since P (getting a six) = 16→16→P(obtaining the third six in 6th throw of the die)=P(2 sixes in first 5 throws)×16P(obtaining the third six in 6th throw of the die)=P(2 sixes in first 5 throws)×16

P (getting 2 sixes in first 5 throws) =C52162565−2=5×41×25365=6253888=C25162565−2=5×41×25365=6253888

P(obtaining the third six in 6th throw of the die)=6253888×16=62523328

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