a die is thrown once find the probability of getting a number lying between 2 and 6
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if die is thrown once total possible outcomes is 6
getting number between 2 to 6 is 3 outcomes
probability is n(e)/n(s)
p(e)=3/6
Hope it helps
getting number between 2 to 6 is 3 outcomes
probability is n(e)/n(s)
p(e)=3/6
Hope it helps
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favourable outcomes= 3,4,5
total outcomes= 1,2,3,4,5,6
probability= no of favourable outcomes/ total no of outcome
= 3/6
therefore probability of getting no between 2 and 6 is 3/6 or we can also say 1/2
total outcomes= 1,2,3,4,5,6
probability= no of favourable outcomes/ total no of outcome
= 3/6
therefore probability of getting no between 2 and 6 is 3/6 or we can also say 1/2
between comes we should should not include 2 and 6
yes
ok it happens
its ok
i have concluded this mistake many times
oh ok
i have concluded this mistake many times
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