Math, asked by nareshbyagari4738, 1 year ago

A diet for a sick person must contain at least 4000 units of vitamins , 50 units of minerals , and 1400 of calories . Two foods A and B , are available at a cost of Rs, 4 and Rs , 3 per unit respec. If one unit of A containa 200 units of vitamin , 1 unit of mineral and 40 calories and one unit of food B contains 100 units of vitamin , 2 units of minerals and 40 calories , find what combination of foods should be used to have the least cost ?

Answers

Answered by sam7867
0
200x+100y>-4000 (20,0)(0,40)
x+2y>-50. (50,0)(0,25)
40x+40y>-1400. (35,0)(0,35)
total cost=4x+3y
minimum cost=120
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