Question

A digital watch is powered by a 1.3 V cell. The cell supplies a current of 4.1 × 10-5 A (0.000041 A) for 1.6 × 107 s.

Answer 1

Answer:

The charge that passes through the cell in this time.

Thank You

Answer 2

Given: 1.3V potential difference, 0.000041A current, time is $1.6*10^{7}$s

To find: charge, resistance, and output power.

Step-by-step explanation:

Step 1 of 3

The formula of charge is $Q=I*t$.

$Q=4.1*10^{-5} *1.6*10^{7} \\Q=6.56*10^{2} C$

Step 2 of 3

The resistance in watch is $R=\frac{V}{I}$

$R=\frac{1.3}{4.1*10^{-5} } \\R=0.317*10^{5} \\R=3.17*10^{4}ohm$

Step 3 of 3

The output power is $P=VI$

$P=1.3*4.1*10^{-5} \\P=5.33*10^{-5}Watt$

[Your question is incomplete, but most probably your full question was - A digital watch is powered by a 1.3 V cell. The cell supplies a current of 4.1 × 10–5 A (0.000041 A)

for 1.6 × 107 s.

Calculate

(a) the charge that passes through the cell in this time,

(b) the resistance of the electrical circuit in the watch,

(c) the output power of the cell.   ]