Question

A disc of mass 10kg and radius 2m rotates about a perpendicular central axis with 10 rev/s. If it is accelerated to 15 rev/s in 10s, f ind the torque.​

Answer 1

Answer:

30rads

Explanation:

Moment of inertia I=

2

mr

2

=

2

10×0.2

2

=0.2 kgm

2

Angular acceleration α=

I

τ

=

0.2

10

=50 rad/s

2

Initial angular velocity w

i

=0

Using w

f

=w

i

+αt

Or w

f

=0+50×6=300 rad/s