A disc of radius 2m and mass 100 kg rolls on a horizontal floor. It's centre of mass has speed of 20cm/s.how much work is needed to stop it
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Hey Dear,
◆ Answer -
W = 4 J
◆ Explaination -
To stop the rolling disc, work must be done to overcome kinetic energy & rotational energy.
W = K.E. + R.E.
W = (1/2)mv² + (1/2)Iω²
W = (1/2)mv² + (1/2)mr²ω²
W = (1/2)mv² + (1/2)mv²
W = mv²
W = 100 × 0.2²
W = 4 J
Therefore, 4 J work will be required to stop the rolling disc.
Thanks for asking..
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