A disc of radius r is cut from a larger disc of radius 4r in such a way that the edge of the hole touches the edge of the disc. The centre of mass of the residual disc will be a distance from the large disc
1)r/5
2)r/4
3)r/3
4)r/2
Answers
Answered by
4
Answer:
option1
Explanation:
area of the residual disc=π(16r^2-r^2)
=15πr^2
then m1/m2=πr^2÷15πr^2
m1/m2=1/15
R1=3r,R2=?
m1r1=m2r2
=m1/m2=3r/15=r/5
Answered by
2
Answer:
r/5 is the answer...
hope it helps
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