Question

A distribution consists of three components with frequencies of 200,250, and 300 having mean of 25 ,10 and 15 respectively. find out the mean of combined distribution n m shah

Answer 1

n1 = 200   x1 = 25 (draw dash on top of x)

n2 = 250   x2 = 10

n3 = 300   x3 = 15

Let x is the mean of the combined distrbution then

x = (n1x1 + n2x2 +n3x3)/(n1 + n2 + n3)

(200x25 + 250x10 + 300x15)/ (200+250+300)

(5000 + 2500 + 4500)/750

12000/750

=16

Answer 2

The mean of combined distribution is 16

Given :

A distribution consists of three components with frequencies of 200,250, and 300 having mean of 25 , 10 and 15 respectively

To find :

The mean of combined distribution

Solution :

Step 1 of 2 :

Write down the given data

Here it is given that a distribution consists of three components with frequencies of 200 , 250, and 300 having mean of 25 ,10 and 15 respectively

Thus we have

n₁ = 25 , n₂ = 10 , n₃ = 15

x₁ = 200 , x₂ = 250 , x₃ = 300

Step 2 of 2 :

Find mean of combined distribution

The mean of combined distribution

$\displaystyle \sf{ = \frac{ \sum \: nx}{ \sum \: n} }$

$\displaystyle \sf{ = \frac{ (200 \times 25) + (250 \times 10) + (300 \times 15)}{ 200 + 250 + 300} }$

$\displaystyle \sf{ = \frac{5000 + 2500 + 4500}{ 750} }$

$\displaystyle \sf{ = \frac{12000}{ 750} }$

$\displaystyle \sf{ = 16 }$

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