A diverging meniscus lens of 1.5 refractive index has concave surface of radii 3 and 4cm . The position of the image if an object is placed 12cm in front of lens is
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Answer:
Explanation:
f
1
=(μ−1)(
R
1
1
−
R
2
1
)
Forgivenconcavelens,R
1
=−3cm,R
2
=−4cm
v
1
−
u
1
=(μ−1)(
−3
1
+
4
1
)
or,
v
1
−
(−12)
1
=(1.5−1)(
12
−4+3
)
or,
v
1
+
12
1
=0.5×
12
−1
=
24
−1
or,
v
1
=−
24
1
−
12
1
=
24
−1−2
=
8
1
or,v=−8cm
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