Question

a diverging mirror of radius of curvature 40 cm forms an image which is half the height of the object.find the object and image position.

Answer 1

Image size is half of that object so magnification is 1/2
-v/u=1/2
u=-2v
R=40cm so f=R/2=20cm
1/v+1/u=1/f
1/v-1/2v=1/f
1/2v=1/f
f=2v
20=2v
v=+10
hope it helped u...

Answer 2

Answer:

Image size is half of that object so magnification is 1/2

-v/u=1/2

u=-2v

R=40cm so f=R/2=20cm

1/v+1/u=1/f

1/v-1/2v=1/f

1/2v=1/f

f=2v

20=2v

v=+10

hope it helped u...

Explanation: