Question

. A doctor's location is at point "A". Appu who is at point "B" wants to visit the doctor. In the map point "A" and point "B" are 2.5 cm. apart. If the scale of map is 1cm. = 50 kilometre. Find how many kilometres Appu has to travel. (write only numerical value)​

Answer 1

Answer:

it 1 cm = 50 km

so 2 cm = 100 km

half km = 25 cm

so 2.5cm =125 km away

Answer 2

Answer:

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A doctor's location is at point "A". Appu who is at point "B" wants to visit the doctor. In the map point "A" and point "B" are 2.5 cm. apart. If the scale of map is 1cm = 50 kilometre. Find how many kilometres Appu has to travel. (Only numerical value)

$\huge{ \frak{ \red{ \dag}{ \pink{An}}{ \color{magenta}{sw}}{ \color{blue}{er}}}}$

$\large{ \frak{ \underline{ \red{To \: find :}}}}$

Distance traveled by Appu to visit doctor.

$\large{ \frak{ \underline{ \pink{Given :}}}}$

$\sf{Doctor's \: location \: = point \:{ ‘A’}}$

${ \sf{Appu 's \: location = point \: ‘ B’}}$

$\sf{Distance \: from \: point \: ‘A’ \: to \: ‘ B’ in \: map = 2.5 \: cm}$

$\sf{1 cm \: in \: map = 50 \: kilometre }$

$\large\frak{\underline{\purple{Formula \: required}}}$

Unitary Method

$\large{ \frak{ \underline{ \color{blue}{ Solⁿ :}}}}$

${ \sf{∵1 cm = 50 \: kilometre}}$

$\sf{∴ 2.5 \: cm = 50 × 2.5 \: cm }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \boxed{ \frak{ \blue{= 125 \: kilometre}}}}$

$\sf{ \red{Hope \: it \: helps...}}$

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