A door frame dimensions 3m×2m is fixed on the wall of dimensions 10×10m.find the total labour charges for painting the wall if the labour charges for painting 1 m square of the wall is 2.50 .
Answers
Step-by-step explanation:
Painting of the wall has to be done excluding the area of the door.
Area of the door = L × b
= 3 × 2m² = 6m²
Area of wall including door = side × side = 10 m ×10 m = 100m²
Area of wall excluding door = (100–6) m² = 92m²
Total labour charges = Rs 2.50 × 94
= Rs 235
Given:
The dimensions of the door and the wall.
To Find:
The total labor charge for painting.
Solution:
The shape of a door is a rectangle and the formula for the area of a rectangle is length multiplied by breath.
Area of the door = Length × Breadth
= 3 × 2
= 6m²
∴ The area of the rectangular door is 6m².
The area of the square can be found by using the formula side² and a wall is also in the shape of a square. So,
Area of the wall = side × side
= 10 × 10
= 100m²
∴ The area of the square wall = 100m²
Now, to find the area of the remaining part = Area of the wall - Area of the door.
= 100 - 6
= 94m²
The cost of painting 1m² of the wall = Rs.2.50 [given]
The cost of painting 94m² of the wall = Area to be painted × cost of painting 1m²
= Rs.2.50 × 94m²
= Rs.235
Therefore, the cost of painting the entire wall = Rs.235