A drawer contains 100 bolts and 200 nuts. half of bolt and half of nuts are rusted. if one item is chosen at random.find the probability that chosen item is rusted or bolt
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Total possible outcomes = {100 + 200} = {300}
Total rusted items = 100÷2 + 200÷2 = 50 + 100 = 150
Now, total bolts are 100 in number and total items are 150 in number.
So, P ( getting a rusted item or a bolt ) = 100/300 + 100/300 = 1/3 + 1/3 = 2/3
Hope the answer is correct...
Total rusted items = 100÷2 + 200÷2 = 50 + 100 = 150
Now, total bolts are 100 in number and total items are 150 in number.
So, P ( getting a rusted item or a bolt ) = 100/300 + 100/300 = 1/3 + 1/3 = 2/3
Hope the answer is correct...
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