A father with 8 children takes them 3 at a time to the zoological gardens, as often as he can without taking the same 3 children together more than once. the number of times each child will go to the garden is
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56 Times and 21 Times.
father will go as often as he gets to pick 3 children from the 8 satisfying the above conditions, i. e number of combinations of 3 children from available 8 which is equal go 8c3= 56 times.
For each child we need to find combination of other 2 children from the remaining 7.
for child answer is 7c2= 21 Times.
father will go as often as he gets to pick 3 children from the 8 satisfying the above conditions, i. e number of combinations of 3 children from available 8 which is equal go 8c3= 56 times.
For each child we need to find combination of other 2 children from the remaining 7.
for child answer is 7c2= 21 Times.
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