a driver accelerates is car first at the rate of 4 metre per second square and then at the rate of 8 metre per second square calculate the ratio of the force is exerted by the engines
Answers
Ratio of force will be - 1:2
Relation of force with mass and acceleration is given by Newton's second law of motion. It explains relation with mathematical equation- F = ma
F represents force, m is for mass of an object and a represents acceleration.
In the question, acceleration at first is - 4 m/s².
Acceleration later is - 8 m/s².
Therefore, with respect to equation, ratio of force acting will be -
F1/F2 = ma1/ma2
F1/F2 = a1/a2
F1/F2 = 4/8
F1/F2 = 1/2
Hence, ratio of force exerted is 1:2.
Answer:
1:2
Explanation:
Force = m × a
In Ist case = F1 = m × a1
= 1 × 4
= 4N
In IInd case = F2 = m × a2
= 1 × 8
= 8N
Ratio of both F1 /F2 = 4N /8N
= 1 / 2
= 1:2
Hope this helps you .
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