Question

$3 (y - 5) \div 4 - 9y = 3 - (y - 3)$

Answer 1

The solution :

Given : 3 ( y - 5 )/4 - 9y = 3 - ( y - 3 )

First open the bracket

3y - 15/4 - 9y = 3 - y + 3

By cross multiplication

3y - 15 - 9y = 4( 3 - y + 3 )

3y - 15 - 36y = 12 - 4y + 12

Now, take the variables on one side and coefficient on another side

3y - 36y + 4y = 12 + 12 + 15

-33y + 4y = 24 + 15

-29y = 39

y = -39/29

★ BE BRAINLY ★

Answer 2

The solution is:-

=> 3(y-5)/4-9y = 3 -(y-3)
In this method firstly we have to break the brackets

=> 3y-15/4 -9y = 3-y+3
After this we have to Multiply crossly

=> 3y-15-9y = 4(3-y+3)

=> 3y-15-36y = 12 -4y +12
Now Set all the Constant term one side and variable term one side Like this,

=> 3y-36y+4y = 12+12+15

=> -33y + 4y = 39

=> -29y = 39

=> -y = 39/29
or
=> y = -39/29


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