Question

A driver being a car travelling at
22ms to stop in 20 second.
(a) What is the car's acceleration?
(b) How far does a travel before
stopping?
- 11m22m)​

Answer 1

a = 0 - 22 /20 = - 11/2

0² - 484 = 2*-11/2*s

-484 /11 = -s

44 = s

Answer 2

Answer:

acceleration is =22/20=1.1m/s^2

distance=22×20-(1/2)(22/20)20^2

=440-220=220m