A driver being a car travelling at
22ms to stop in 20 second.
(a) What is the car's acceleration?
(b) How far does a travel before
stopping?
- 11m22m)
Answers
Answered by
6
a = 0 - 22 /20 = - 11/2
0² - 484 = 2*-11/2*s
-484 /11 = -s
44 = s
Answered by
4
Answer:
acceleration is =22/20=1.1m/s^2
distance=22×20-(1/2)(22/20)20^2
=440-220=220m
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