Question

A farmer moves along the
boundary of a square field of side
10 m in 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?


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Answer 1

Total time= 2min 20 s

= 2×60s + 20s

= 140s

In 40s, no. of rounds made= 1

So, in 140s no. of rounds made = $\frac{1}{40} × 140$

= 3.5 rounds

If the farmer starts from point A , after 3.5 rounds he will be in point C.

So, his displacement from A to C can be find out through Pythagoras theorem.

(AC)^2 = (AB)^2 + (BC)^2

(AC)^2 = (10)^2 + (10)^2

(AC)^2 = 100 + 100

(AC)^2 = 200

AC= √200

= 14.143 m

Answer 2

Answer:

Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

Explanation:

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