A father age is four times that of his son. before 8 years the father age was 16 times that of his son .find their present ages
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let the son's age be x
so father age is 4x
4x-8=16(x-8)
4x-8=16x-128
12x=120
x=10
so the present age of son is 10
so the present age of father is 4(10)=40
so father age is 4x
4x-8=16(x-8)
4x-8=16x-128
12x=120
x=10
so the present age of son is 10
so the present age of father is 4(10)=40
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