The area of a rectangle is 672 sum and one side is 16 m find the perimeter of the rectangle
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Answered by
4
Area of rectangle= lb=672.
If breadth is 16, then l=672/16
=42 m.
Perimeter=2(l+b)
=2(42+16)
=2(58)
=116 m.
Cheers. Mark brainliest.
If breadth is 16, then l=672/16
=42 m.
Perimeter=2(l+b)
=2(42+16)
=2(58)
=116 m.
Cheers. Mark brainliest.
Answered by
2
Hey frnd!!!
Given ;
Area of the rectangle =672
and one side that is let l = 16 m
To find :the perimeter=?
solution:
area of rectangle =l*b
672=16*b
672/16= b
breadth =42 m
Perimeter of a rectangle = 2(l+b)
= 2(16+42)
=2*58
=116m
Given ;
Area of the rectangle =672
and one side that is let l = 16 m
To find :the perimeter=?
solution:
area of rectangle =l*b
672=16*b
672/16= b
breadth =42 m
Perimeter of a rectangle = 2(l+b)
= 2(16+42)
=2*58
=116m
Hemamalini15:
Mark as brainliest pls
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