A father is 3 time's as old as his son. After 15 years, he will be twice as old as his son, what are their present ages?
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Answered by
3
Let preset age of
Son = x
Father = y
According to question
y = 3x —-(1)
After 15 years
(y + 15) = 2 * (x + 15)
y + 15 = 2x + 30
From equation (1) y = 3x
3x + 15 = 2x + 30
x = 15
Hence present age of
Son = x = 15 years
Father = y = 3x = 45 years
Son = x
Father = y
According to question
y = 3x —-(1)
After 15 years
(y + 15) = 2 * (x + 15)
y + 15 = 2x + 30
From equation (1) y = 3x
3x + 15 = 2x + 30
x = 15
Hence present age of
Son = x = 15 years
Father = y = 3x = 45 years
Answered by
4
Hey friend,
Here's your answer
Here's your answer
Attachments:
Hasty:
My calculation is right
Check from 3x + 15 = 2x
Ok you mean to say that 15will be added at both the sides???
No. You wrote 3x + 15 = 2x then 3x - 2x = 15. In second equation it should be 3x - 2x = -15 which will give you x = -15. Age cannot be negative. So your first equation itself is incorrect. Check my answer and correct it.
Now is it right
Yes. Now it’s correct.
Thanks for helping me!!!
Are you in 9th
12+
Ok
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