Math, asked by kdm0006, 11 months ago

a father is 3 times old as his son five yrs later father will be 2 and a half times old as son find present age of father and son

Answers

Answered by samqueen38
0

Answer:

Two years ago, father was three times as old as his son and two years hence, twice his age will be equal to five times that of his son.

. Son's present age X = 14 years. Father's present age = 38 years.

Step-by-step explanation:

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Answered by aaravbhatia12506knp
0

Step-by-step explanation:

Let the age of the son be x

Fathers age = 3x

5 years later,

Age of son = 5+x

Fathers age = 2.5(5+ x)

3x + 5 = 2.5 (5+ x )

3x + 5 = 12.5 × 2.5x

3x/2.5x = 12.5 - 5

1.2x = 7.5

x = 6.25

Age of son ( at present) = 6.25 years

Age of father ( at present ) =

3×6.25

18.75 years

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