Question

A father is 4 times as old as his son and the son is 36 years younger than the father
Find their ages.​

Answer 1

Answer:

Step-by-step explanation:  Hii friend,

Let the age of father and son be X and Y year's.

According to question,

X = 4Y.....(1)

Again,

Y = X-36.....(2)

Putting the value of X in equation (2)

Y = X-36

Y = 4Y -36

4Y-Y = 36

3Y = 36

Y = 36/3

Y = 12

Age of son = Y = 12 years.

And,

Age of father = 4Y = 4 × 12 = 48 years.

Hence,

Age of father and son is 48 and 12 years.

HOPE IT WILL HELP YOU...... :-)

 

Answer 2

$\red{♡Answer♡}$

let the age of father be $\pink{x \ years}$

and let the age of son be $\green{y \ years}$

By given condition

x=4y---(1)

x-y=36

3y=36

y=12

x=48

hence age of father is $\orange{48yrs}$

and age of son is $\purple{12yrs}$

hope it helps .

☆☆☆