Show that points (2,0), (-2,0) and (0,2) are vertices of triangle
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Vertex A of the given triangle is ( 0,0). Vertex B(2,0) & vertex C (0,2)
If these points are plotted on XY coordinate plane. We get a right triangle, right angledat A origin. AB on X axis & AC on Y axis. BC is the hypotenuse.
=> its circumcentre will be the mid point( M) of hypotenuse BC. & Orthocrntre will be the origin A.
Coordinates of A = (0,0) & coordinates of M = (1,1)
So distance between A & M = √{(1–0)² + (1–0)²} ( by distance formula)
= √(1+1) = √2 unit
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