Question

A Father is 40 years elder than his son, after 10 years father will be twice as old as his son.
Find their present ages.

Answer 1

Answer:

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age of father =40

son=x

equation is

2x+10=40

2x=40-10

so

2x=30

x=30/2

so x= 15

son =x=15

father=2x= 15

Answer 2

Answer:

Son is 30 and father is 70.

Step-by-step explanation:

To solve the problem, find a suitable age that is two times older or younger thfan the other one, depending on which age you want to find frist.

Then, you get the difference and it must be 40 years.

Assume b is the son's age after 10 years.

The father's age will be 2b.

2b - b = 40

b = 40

After 10 years, son will be 40 and the father will be 80.

You subtract each age with 10 and you will get their present ages.

Son's present age = 40 - 10 = 30

Father's present age = 80 - 10 = 70

Hope this answer help you.