A father is 7 times as old as his son. Two years ago the father was 13 times as his son . Find their present ages
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Let the present age of father be x and of son be y .
Atq=7y=x. Eq1
Now, atq=(x-2(=14(y-3)
7y-2=13y-26(putting value of x fom eq1)
-2+26=13y-7y
24=6y
y=4
Putting value of y in eq 1
7y=x
7*4=x
x=24
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