Math, asked by MirzaJahirHossain, 1 year ago

a father is four times as old as his son in four year time he will be three year times as old as his son what are their present ages.?

Answers

Answered by littyissacpe8b60
2

Son = a

father = 4a

After 4years

Son = a + 4

Father 4a + 4   or  3(a+4)

4a + 4 = 3a + 12

a = 8

Son's present age = 8 years

Father's present age = 32years


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