Question

a father is twice as old as his son the sum of their ages is 49 find their ages​

Answer 1

Answer:

Let the age of son be x

Age of father=2x

According to the condition,

2x+x=48

x=48/3=16

(i think it 48 not 49 check)

Answer 2

Step-by-step explanation:

let the age of the son be X and the age of the father be 2x

then:

x+2x=48 Add like terms

3x=48 (Divide out by 3 both sides)

x=16

So the age of the son is 16 and that of the father is 32

(But their sum is not 49, it is 48)