Question

A father is twice that of his son and 8 yeras and the father's age will be 7/4 times the son age.Find the present age of the son.​

Answer 1

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Answer:

Present age of son = 24 years

Step-by-step explanation:

Let the age of son be x.

Father's age = 2x

8 years hence,

Age of son = (x + 8) years

Age of father = (2x + 8) years

According to the question,

2x + 8 = 7/4 (x + 8)

4(2x + 8) = 7(x + 8)

8x + 32 = 7x + 56

8x - 7x = 56 - 32

x = 24

Therefore, press age of son = 24 years

Answer 2

QUESTION:

• The Present age of a Man is double the age of his Son. After 8 Years, the ratio of their ages Will Be 7:4. Find the present ages of the Man and his Son.

GIVEN:

• The Present Age of a Man is Double the Age of His Son.
• After 8 Years, the Ratio of Their Ages Will Be 7:4.

TO FIND:

• Present ages of the Man and his Son.

SOLUTION:

Let the present age of Son be x years, then the Man's age will be 2x years.

After, 8 years their age's will be :

• x + 8
• 2x + 8

According to the question, after 8 years their age's are in the ratio 7:4.

• (x + 8)/(2x + 8) = 7/4
• 7x + 56 = 8x + 32
• 7x - 8x = 32 - 56
• -x = -24
• x = 24

ANSWER:

• Son (x) = 24 years
• Man (2x) = 48 years

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