a⋅(n+y)=10y+32 solve for y
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Answer: 0 = 0
Step-by-step explanation:
y = (-n/a)
y = (-32/10)
a[n+(-n/a)]= 0
kyonki n-n = 0 or a/a = 0
10(-32/10)+32= 0
kyonki -32+32 = 0 or 10/10 = 0
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