Math, asked by rish0810, 1 year ago

A father's age is thrice the sum of the ages of his two children. After 5 years his age will be twice the sum of their ages. How old is the father?

Answers

Answered by dhathri123
4
hi friend,

let the two children age be x and y


given father's age is 3(x+y)


after 5 years , father's age will be 3x+3y+5--------(1)


two children age will be x+5,y+5

given , father's age will be 2(x+y+10)----(2)


equating (1) and (2)

3x+3y+5=2x+2y+20

=x+y=15-----(3)


given that the present age of father is 3(x+y)=3(15)=45


I hope this will help u :)
Answered by sreedhar2
1
Hey there!

Let the age of two children be x and y.

Then her father's age = Thrice the sum of ages of his two children = 3(x+y).

After five years,

Father's age = 3(x+y) +5 years.------(1)
Thier childrens age = x+5 years and y+5 years.

But ATQ father's age will be twice of his childrens.

So his age = 2( x+5+y+5) = 2(x+y+10) ----(2)

Equating (1) and (2)

3(x+y) +5 = 2(x+y+10)

3x+3y+5 = 2x+2y+20

3x-2x + 3y-2y = 20-5

x+y = 15.

Father's age = 3(x+y) = 3(15) = 45.

So, Father is 45 years old.

:)


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