A father's age is thrice the sum of the ages of his two children. After 5 years his age will be twice the sum of their ages. How old is the father?
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Answered by
4
hi friend,
let the two children age be x and y
given father's age is 3(x+y)
after 5 years , father's age will be 3x+3y+5--------(1)
two children age will be x+5,y+5
given , father's age will be 2(x+y+10)----(2)
equating (1) and (2)
3x+3y+5=2x+2y+20
=x+y=15-----(3)
given that the present age of father is 3(x+y)=3(15)=45
I hope this will help u :)
let the two children age be x and y
given father's age is 3(x+y)
after 5 years , father's age will be 3x+3y+5--------(1)
two children age will be x+5,y+5
given , father's age will be 2(x+y+10)----(2)
equating (1) and (2)
3x+3y+5=2x+2y+20
=x+y=15-----(3)
given that the present age of father is 3(x+y)=3(15)=45
I hope this will help u :)
Answered by
1
Hey there!
Let the age of two children be x and y.
Then her father's age = Thrice the sum of ages of his two children = 3(x+y).
After five years,
Father's age = 3(x+y) +5 years.------(1)
Thier childrens age = x+5 years and y+5 years.
But ATQ father's age will be twice of his childrens.
So his age = 2( x+5+y+5) = 2(x+y+10) ----(2)
Equating (1) and (2)
3(x+y) +5 = 2(x+y+10)
3x+3y+5 = 2x+2y+20
3x-2x + 3y-2y = 20-5
x+y = 15.
Father's age = 3(x+y) = 3(15) = 45.
So, Father is 45 years old.
:)
Let the age of two children be x and y.
Then her father's age = Thrice the sum of ages of his two children = 3(x+y).
After five years,
Father's age = 3(x+y) +5 years.------(1)
Thier childrens age = x+5 years and y+5 years.
But ATQ father's age will be twice of his childrens.
So his age = 2( x+5+y+5) = 2(x+y+10) ----(2)
Equating (1) and (2)
3(x+y) +5 = 2(x+y+10)
3x+3y+5 = 2x+2y+20
3x-2x + 3y-2y = 20-5
x+y = 15.
Father's age = 3(x+y) = 3(15) = 45.
So, Father is 45 years old.
:)
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