Math, asked by abbasmohd299, 9 months ago

A fathers age is 7 times as old as his son . Two years ago the father was 13 times as old as his son . What are their present ages

Answers

Answered by Anonymous
3

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<marquee>ItzHarsh★</marquee>

Given that father was 13 times old as his son. x = 4. if the age of son is 4 then the age of father will be 7 * 4 = 28. Their present ages are son = 4 years and his father age = 28 years.

Answered by vaarunisaxena
3

Answer:

Given that father was 13 times old as his son. x = 4. if the age of son is 4 then the age of father will be 7 * 4 = 28. Their present ages are son = 4 years and his father age = 28 years.

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