Question

A fathers age was three times the age oif his son .Five year ago father age was four time the age of his son .The age of sonis

Answer 1

Answer:

Let age of son be x and age of father be y

y=3x

Acc to condition,

(y-5)=4(x-5)

y-5=4x-20

3x-5=4x-20

15=x

Therefore present age of son=15 years and age of father

y=3(15)

y=45

Therefore present age of father is 45 years.

Answer 2

The age of son will be "15". Further explanation is given below.

Step-by-step explanation:

Let the age of son= x, and

the age of father= y

age of father= 3(the age of son)

age of father=3x

According to the question, five years ago

⇒ (y-5)=4(x-5)

⇒ y-5=4x-20

On putting the value of y in the above equation, we get

⇒ 3x-5=4x-20

⇒ -5+20=4x-3x

⇒ x=15

Therefore, age of son = x

                                     = 15

              age of father= 3x

                                     = 3×15

                                     = 45

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