Science, asked by srilu19, 11 months ago

A fixed capacitor of reactance -j. 02 ohm is connected in parallel across a series combination of a fixed inductor of reactance j0.01 ohm and a variable resistance R, as R is varied from zero to infinity the locus of admittance of LCR circuit will be​

Answers

Answered by mandalbabita10
0

Answer:

Explanation:

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Answered by sarahssynergy
1

The locus of admittance of LCR circuit will be​ diameter j100 and center at zero.

Explanation:

Y = 1/-j0.02 + 1/(R+j0.01)

when R=0

Y= 1/-j0.02 +1/(0+j0.01) = j50 -j100 = 50∠-90°

when R=0.01

Y= 1/-j0.02 + 1/(0.01+j0.01) = j50+(0.01-j0.01)/2(0.01)² = 50

when R=∞

Y= 1/-j0.02 +1/∞ = j50 =50∠90°

So, locus of Y is a semi-circle of diameter j100 and center at zero

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