Math, asked by samirsrivastava1, 1 year ago

A floor is 4.5 m long and 3.6 m wide . A 6cm square tiles cost rs 23.25 what will be the cost to cover the floor with these tiles

Answers

Answered by pinquancaro
179

Answer:

The cost to cover the floor with these tiles is Rs.627750.      

Step-by-step explanation:

Given : A floor is 4.5 m long and 3.6 m wide. A 6 cm square tiles cost Rs. 23.25

To find : What will be the cost to cover the floor with these tiles?

Solution :

A floor is 4.5 m long and 3.6 m wide.

The area of the floor is A=l\times b

A=4.5\times 3.6

A=16.2m^2

Converting m into cm,

1 m = 100 cm

1 m² = 10000 cm²

So, 16.2m^2=16.2\times 10000=162000cm^2

Area of square tile is 6 cm².

Number of tiles required to cover the floor is

n=\frac{\text{Area of floor}}{\text{Area of tile}}

n=\frac{162000}{6}

n=27000

Cost of 1 tile is Rs.23.25.

Cost of 27000 tile is 27000\times 23.25=Rs.627750

Therefore, The cost to cover the floor with these tiles is Rs.627750.

Answered by yashvardhanbehera
33

Answer:

The cost to cover the floor with these tiles is Rs.627750.      

Step-by-step explanation:

Given : A floor is 4.5 m long and 3.6 m wide. A 6 cm square tiles cost Rs. 23.25

To find : What will be the cost to cover the floor with these tiles?

Solution :

A floor is 4.5 m long and 3.6 m wide.

The area of the floor is

Converting m into cm,

1 m = 100 cm

1 m² = 10000 cm²

So,

Area of square tile is 6 cm².

Number of tiles required to cover the floor is

Cost of 1 tile is Rs.23.25.

Cost of 27000 tile is

Therefore, The cost to cover the floor with these tiles is Rs.627750.

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