Math, asked by ananyadey2000, 1 month ago

A floor is 4.5m long and 3.6m wide. A 6cm square tile costs rupees 23.25, what will be the cost to cover the floor with these tiles?
(please give step by step explanation)
Thanks!!

Answers

Answered by BrainlyBAKA
1

"Length of the floor = 4.5 m

= (4.5 × 100) cm = 450 cm

Width of the floor – 3.6 m – (3.6 × 100) cm = 360 cm

∴ Area of the floor – (450 × 360) cm2 = 162000 cm²

Side of a square tile = 6 cm

∴ Area of one square tile = (6 × 6) cm2 = 36 cm²

Number of tiles required to cover the floor

= Area of floor/ Area of one tile

= 4500

Now, cost of one tile = ₹ 23.25

∴ Cost of 4500 tiles =₹ (23.25 × 4500)

= ₹ 104625

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Answered by barani79530
1

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