a floor is 40 m long and 15 m board it's covered with the tiles each measuring 60 CM by 50 cm find the number of tiles required to cover the floor
Answers
Answered by
2
so the floor is 40 m =40×100=4000cm long and 15 m=15×100=1500 cm board
if the measure of each tiles is 60cm and 50 cm then the number of tiles is
(4000×1500)/(60×50)
= 400×50
=20000 【Answer】
if the measure of each tiles is 60cm and 50 cm then the number of tiles is
(4000×1500)/(60×50)
= 400×50
=20000 【Answer】
aliza7:
answer is wrong real answer is 2000
Answered by
0
Area of floor=l×b
=40×15
=6000m^2
Area of tile=lb
=50×60
=3000cm^2
No of tiles=area of floor/area of one tile
=(6000×100)/3000
=200
200 tiles are required
=40×15
=6000m^2
Area of tile=lb
=50×60
=3000cm^2
No of tiles=area of floor/area of one tile
=(6000×100)/3000
=200
200 tiles are required
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