Question

A floor which 15m×8m is to be laid with tiles measuring 50cm by 25cm find the number of tiles required . Further 'if a carpet is laid on the floor so that a space of 1 m exists between its edge and the edge of the floor .What fraction of the floor is uncovered

Answer 1

1st change all quantities in same unit

we have area of floor= 1500cm×800cm=1200000cm^2

surface area of a tile=50cm×25cm=1250cm^2

so no of tiles required =1200000/1250=8160

now of carpet is laid on floor so so that a space 1m between its edge and edge of floor

then lenght of carpet=15m-2m=13m
and breadth =8m-2m=6m

so area region covered by carpet =13m×6m=78m^2=780000cm^2

so area of uncovered region=1200000cm^2-780000cm^2=420000cm^2

so fraction of uncovered region=1200000/420000=20/7

Hope it will be helpful.

Answer 2

Area Of Floor = L × B
= 15×8
A = 120 sq. m.

Tiles Area = L×B
= 50×25
= 1250 sq. cm.

Now, The Area of Floor is in metre but the areas of tiles is in centimeter so, now we need the area of floor to convert into centimeter from metre.

1m=100cm
120m=12000cm

Now,
= Area of Floor ÷ Area of Tiles
= 12000÷1250
= 9.6 tiles

Given,
A carpet is laid down on the floor and 1m side is remaining from all sides. So,
= 12000-(4)
= 12000-4
= 11996 sq.cm.
Therefore, 11996 sq. cm. left for the carpet.


Now, bro sorry this much only help I can give to you remaining you have to solve cause O am getting only 5 points for solving only one question amigo.

No need to mark me as the brainliest one.