Question

A floral design on a floor is made up of 16 tiles which are triangular the sides of the triangle being 9cm 28cm 35cm find the cost of polishing the tiles at the rate of 50 paise per centimetre square

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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♠ Refer the attachment for the figure.


♠ Given -

• First side of the triangular design, a = 9 cm

• Second side of the triangular design, b = 28 cm

• Third side of the triangular design, c = 35 cm.



♠ Then,

• Perimeter (p) of the triangular design,

= a + b + c

= 9 + 28 + 35

= 72 cm



• And, semi perimeter (s) of the triangular design,

= p/2

= 72/2

= 36 cm



♠ Then, by Heron's formula, area of the triangular design,

= √[s (s - a)(s - b)(s - c)]

= √[36 (36 - 9) (36 - 28) (36 - 35)]

= √(36 × 27 × 8 × 1)

= √7776

= 88.2 cm² (approx)



♠ Given that there are 16 such designs.


→→→ Area of all the designs,

= 16 × 88.2

= 1411.2 cm²



♠ Given that cost of polishing 1 cm² is 50 paise = 0.5 Rs.


→→→ Cost of polishing 1411.2 cm²,

= 1411.2 × 0.5

= 705.6 Rs.


•°• Cost of polishing the tiles = 705.6 Rs. (approx)
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$<marquee>Thank you.</marquee>$