Question

A FLOORING TILE HAS SHAPED OF PARALLELOGRAM WHOSE BASE IS 24 cm AND HEIGHT IS 10 cm . HOW MANY TILES REQUIRED TO COVER A FLOOR OF AREA
1080m ?

Answer 1

area of parallelogram=base*height
24*10=240cm^2
10800000/240=

Answer 2

Given:

• Base of the flooring tile = 24 cm = 0.24 m
• Height of the flooring tile = 10 cm = 0.10 m

To Find:

Number of tiles required to cover a floor of area 1080 m

Formula:

Area of flooring tile = Base × Altitude

Solution:

Base of the flooring tile = 24 cm = 0.24 m

Height of the flooring tile = 10 cm = 0.10 m

Area of flooring tile = Base × Altitude

Substituting the formula,

$:\implies 0.24 \times 0.10\\:\implies 0.024$

Area of flooring tile $\implies \boxed{0.024 \: m^{2} }$

Now, finding the tiles required,

∴ Number of tiles required to cover the floor = $\frac{Area \: of \: floor }{Area \: of \: one \: tile} = \frac{1080}{0.024}$

$:\implies \boxed{45000 \: tiles}$

Hence, 45000 tiles are required to cover the floor.