a force acting at an angle of 60 ° with y axis it's x component 5n the force is
Answers
Answer:
x - axis
f
x
=fcos60
⇒10×
2
1
=5N
y -axis
f
y
=fsin60
⇒10×
2
3
=5
3
N
A force is acting at an angle of 60 degree with an x axis. If the x component of force is 50 , what is the resultant force and y component of force?
R = Resultant Force
Fy= Force at y
Fx= Force at x
R = Fx + Fy
Fx=50(?)
the Force in the x direction is given as 50 something.
the Force Resultant direction is 60 degrees from x axis
Fx=R cos(60)=50(?)
R = 50(?)/cos(60)
cos(60)=1/2
-——————————
R= 100(?)
_______________________
Fy=R sin(60)
sin (60)=square root of 3 / 2
Fy = 100 • square root of 3 / 2
-——————
Fy = 86.6(?)
——————A force is acting at an angle of 60 degree with an x axis. If the x component of force is 50 , what is the resultant force and y component of force?
R = Resultant Force
Fy= Force at y
Fx= Force at x
R = Fx + Fy
Fx=50(?)
the Force in the x direction is given as 50 something.
the Force Resultant direction is 60 degrees from x axis
Fx=R cos(60)=50(?)
R = 50(?)/cos(60)
cos(60)=1/2
-——————————
R= 100(?)
_______________________
Fy=R sin(60)
sin (60)=square root of 3 / 2
Fy = 100 • square root of 3 / 2
-——————
Fy = 86.6(?)
——————