Question

a force acting at an angle of 60 ° with y axis it's x component 5n the force is​

Answer 1

Answer:

x - axis

f

x

=fcos60

⇒10×

2

1

=5N

y -axis

f

y

=fsin60

⇒10×

2

3

=5

3

N

Answer 2

A force is acting at an angle of 60 degree with an x axis. If the x component of force is 50 , what is the resultant force and y component of force?

R = Resultant Force

Fy= Force at y

Fx= Force at x

R = Fx + Fy

Fx=50(?)

the Force in the x direction is given as 50 something.

the Force Resultant direction is 60 degrees from x axis

Fx=R cos(60)=50(?)

R = 50(?)/cos(60)

cos(60)=1/2

-——————————

R= 100(?)

_______________________

Fy=R sin(60)

sin (60)=square root of 3 / 2

Fy = 100 • square root of 3 / 2

-——————

Fy = 86.6(?)

——————A force is acting at an angle of 60 degree with an x axis. If the x component of force is 50 , what is the resultant force and y component of force?

R = Resultant Force

Fy= Force at y

Fx= Force at x

R = Fx + Fy

Fx=50(?)

the Force in the x direction is given as 50 something.

the Force Resultant direction is 60 degrees from x axis

Fx=R cos(60)=50(?)

R = 50(?)/cos(60)

cos(60)=1/2

-——————————

R= 100(?)

_______________________

Fy=R sin(60)

sin (60)=square root of 3 / 2

Fy = 100 • square root of 3 / 2

-——————

Fy = 86.6(?)

——————