Question

A force constant of a weightless spring is 16n/m a body of mass 1 kg suspended from it is pulled down through 5 cm was released the maximum kinetic energy of system ( spring + body)

Answer 1

Answer:

2*10raise to -2J

Explanation:

given

k=16N/m

m=1kg

x=5cm=5*10raise to -2m

therefore KE=1/2kx2-1/2k'2

=1/2*16*0.05wholesq.

=2*10raise to -2

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Answer 2

The maximum kinetic energy of system is 0.02 J.

Explanation:

It is given that,

Mass of the body, m = 1 kg

Force constant of the spring, k = 16 N/m

Distance covered by the spring, x = 5 cm = 0.05 m

We need to find the maximum kinetic energy of system when it was released. It can be calculated using conservation of energy as :

Maximum kinetic energy = maximum elastic potential energy

$E=\dfrac{1}{2}kx^2$

$E=\dfrac{1}{2}\times 16\ N/m\times (0.05\ m)^2$

E = 0.02 J

So, the maximum kinetic energy of system is 0.02 J. Hence, this is the required solution.

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Maximum elastic potential energy

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